+0  
 
0
19
1
avatar

What is the sum of the smallest and second-smallest positive integers satisfying the congruence 27a = 40 (mod 43)?

 
 Sep 12, 2021
 #1
avatar
0

 27a = 40 (mod 43)?

 

a =43n + 19, where n==0, 1, 2, 3.............etc.

 

The smallest positive integer ==19 x 27 ==513

 

The 2nd smallest positive integer ==513 + 43 ==556 {However, if the 2nd smallest must be  multiple of 27, then the answer would be:[43 + 19==62 x 27==1674}

 
 Sep 12, 2021

34 Online Users

avatar