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Find a six-digit multiple of $64$ that consists only of the digits $2$ and $4$.

 Jul 7, 2024
 #1
avatar+1256 
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There isn't really a model you can follow to solve this problem. 

However, there are multiple numbers that satisfy the condiitions given. 

First, we have

\(244224 \mod 64 = 0\)

 

Since the final result is 0, then 244224 is an answer. 

 

Also, let's note that another number, 

\(444224 \mod 64 = 0\) also works. 

 

So 444224 satisfies the equation as well. 

 

Thus, the two answers we have are \(444224, 244224\)

 

Thanks! :)

 Jul 7, 2024

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