Find a six-digit multiple of $64$ that consists only of the digits $2$ and $4$.

RedDragonl Jul 7, 2024

#1**+1 **

There isn't really a model you can follow to solve this problem.

However, there are multiple numbers that satisfy the condiitions given.

First, we have

\(244224 \mod 64 = 0\)

Since the final result is 0, then 244224 is an answer.

Also, let's note that another number,

\(444224 \mod 64 = 0\) also works.

So 444224 satisfies the equation as well.

Thus, the two answers we have are \(444224, 244224\)

Thanks! :)

NotThatSmart Jul 7, 2024