We can keep couting up and up until we get prime numbers.
First, we have \(101\). Notice it's only divisble by 1 and itself, so there's the first prime.
All the even numbers obviously don't work, so we skip them.
Next, we have \(103\). It also is only divisble by 1 and itself, so that's the second prime.
Third, we have 105. It's divisble by 5, so it doesn't work.
Then, we have \(107\), which is also a prime number.
\(109\) is also prime, so we count that as our fourth prime number
111 is divisble by 3 and 37, so it doesn't work.
However, \(113\) is prime, so that's the smallest.
So 113 is our answer.
Thanks! :)
We can keep couting up and up until we get prime numbers.
First, we have \(101\). Notice it's only divisble by 1 and itself, so there's the first prime.
All the even numbers obviously don't work, so we skip them.
Next, we have \(103\). It also is only divisble by 1 and itself, so that's the second prime.
Third, we have 105. It's divisble by 5, so it doesn't work.
Then, we have \(107\), which is also a prime number.
\(109\) is also prime, so we count that as our fourth prime number
111 is divisble by 3 and 37, so it doesn't work.
However, \(113\) is prime, so that's the smallest.
So 113 is our answer.
Thanks! :)