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number theory

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Find the value of $\sum _{n=1}^{99}9876^{n} \text{(mod 100)}$

Guest Jun 25, 2020

1⁺⁰ Answers

+33657

+1

As follows:

9876ⁿ (mod(100) = 9876 (mod(100)) = 76

Hence $\Sigma_{n=1}^{99}9876^n (\mod(100) ) = 99*76 = 7524$

Alan Jun 25, 2020

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