What is the remainder when 10! is divided by 27? (Reminder: If n is a positive integer, then n! stands for the product 1*2*3 ... *n)
10! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
27 = 3 x 3 x 3
When you divide 10! by 27 (and cancel out the corresponding 3s) you get: 10 x 8 x 7 x 2 x 5 x 4 x 3 x 1
with no remainder; remainder = 0.
