When the digits in the number 2005 are reversed we obtain the number 5002 and 5002=a*b*c such that a, b and c are three distinct primes. What are a, b, and c?
When the digits in the number 2005 are reversed we obtain the number 5002 and 5002=a*b*c such that a, b and c are three distinct primes. What are a, b, and c?
2 x 41 x 61 = 5002 but I don't know what reversing the order of the numbers has to do with anything.
