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When the digits in the number 2005 are reversed we obtain the number 5002 and 5002=a*b*c such that a, b and c are three distinct primes. What are a, b, and c?

 Nov 6, 2021
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When the digits in the number 2005 are reversed we obtain the number 5002 and 5002=a*b*c such that a, b and c are three distinct primes. What are a, b, and c?

 

2 x 41 x 61 = 5002 but I don't know what reversing the order of the numbers has to do with anything.  

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 Nov 7, 2021

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