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avatar+1839 

Find a six-digit multiple of $64$ that consists only of the digits $2$ and $4$.

 Aug 3, 2024
 #1
avatar+1918 
+1

We just have

 

\(64 \cdot 3,816 = 244,224 \)

\(244224 \pmod{ 64} \equiv 0\)

 

244224 works. 

 

Thanks! :)

 Aug 3, 2024
edited by NotThatSmart  Aug 3, 2024

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