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Determine the four-digit natural numbers of the form abcd with property (a-1)(b-2)(c-3)(d+2019)=2020.

 Aug 22, 2020
 #1
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I found 2 such numbers:

 

2121,  2341 

 Aug 22, 2020
 #2
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(a-1)(b-2)(c-3)(d+2019)=2020

a = 2

b =3

c =4

d =1

(2 - 1)(3 - 2)(4 - 3)(1 + 2019) = 2020

1*1*1*2020 = 2020

a = 2

b = 1

c = 2

d = 1

(2 - 1)(1 - 2)(2 - 3)(1 + 2019) = 2020

1*(-1)*(-1)*2020 = 2020

 

laugh

 Aug 22, 2020
edited by Guest  Aug 22, 2020

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