How many positive five-digit numbers are divisible by each of 7, 8, 9, 10, and 11?
It must be divisable by 7, 2^3, 3^2, 2, 5 and 11
That is 7,2^3, 3^2, 5 ,11 (the 2 is included in the 2^3)
7*8*9*5*11 = 27720
27720*1=27720
27720*2 = 55440
27720*3= 83160
that is it.
