Numbers

We have

$(6032)_{12} = (6 × 12^3) + (0 × 12^2) + (3 × 12^1) + (2 × 12^0) = (10406)_{10}$

How it works is that for every digit of 6032, we mulitply it by a power of 12 starting from 0. 

So our final answer is 10406. 

Thanks! :)