+0  
 
0
220
3
avatar+929 

No calc please

 May 28, 2019
 #3
avatar+8873 
+3

The possible values of  n  are:

 

1, 5, 7, 11, 13, 17, 19, 23, 25, 29, 31, 35, 37, 41, 43, 47

 

And the elements in the set are:

 

\(\frac{1}{24}, \frac{5}{24}, \frac{7}{24}, \frac{11}{24}, \frac{13}{24}, \frac{17}{24}, \frac{19}{24}, \frac{23}{24}, \frac{25}{24}, \frac{29}{24}, \frac{31}{24}, \frac{35}{24}, \frac{37}{24}, \frac{41}{24}, \frac{43}{24}, \frac{47}{24}\)

 

So the sum of the elements in the set   =   \(\frac{384}{24}\)   =   16

 May 30, 2019

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