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dr = b(cosθdr + rsinθdθ)

 Oct 21, 2021
 #1
avatar+32991 
+3

Like so:

You might prefer to express this as \(\theta=...\) in which case I'll leave you to do the rearrangement.

 Oct 21, 2021
 #2
avatar+117483 
0

Thanks Alan,

I was hoping you would look at this one  wink

 Oct 21, 2021

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