at a street racket sold small apples for 25 cants and small pears for 30 cents and small oranges for 40 cents at the end of the day the farmer had the same amount of money from each type of fruit what is the least amount of money the farmer could have made selling pears
+130511 We need to get a common denominator between 25, 30 and 40
25 = 5^2
30 = 2 x 3 x 5
40 = 2^3 x 5
So....the common denomimator = 2^3 x 3 x 5^2 = 8 x 3 x 5 = 24 x 25 = 600
To make the same amount of money from each he would have sold
600/25 apples = 24 apples
600/30 pears = 20 pears and
600/40 oranges = 15 oranges
So....20 pears is the fewest that he could have sold if the money he made from selling each type of fruit was equal.......and 20 pears would have cost $6.00
+130511 We need to get a common denominator between 25, 30 and 40
25 = 5^2
30 = 2 x 3 x 5
40 = 2^3 x 5
So....the common denomimator = 2^3 x 3 x 5^2 = 8 x 3 x 5 = 24 x 25 = 600
To make the same amount of money from each he would have sold
600/25 apples = 24 apples
600/30 pears = 20 pears and
600/40 oranges = 15 oranges
So....20 pears is the fewest that he could have sold if the money he made from selling each type of fruit was equal.......and 20 pears would have cost $6.00
