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 [OH-] concentration

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What is the [OH-] concentration if the ph =9.55?

 Dec 4, 2016

Best Answer 

 #1
avatar+37091 
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-Log[OH-] = pOh           pH +pOh = 14   so pOH = 4.45

 

-log[OH-]= 4.45

[OH] = 3.55 x 10^-5  M

 Dec 4, 2016

1+0 Answers

 #1
avatar+37091 
+5
Best Answer

-Log[OH-] = pOh           pH +pOh = 14   so pOH = 4.45

 

-log[OH-]= 4.45

[OH] = 3.55 x 10^-5  M

ElectricPavlov Dec 4, 2016

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