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in the following expression: x-(21*x\100)=275000 how does that become x=27500000\79?
 Mar 22, 2014
 #1
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What I want someone to do is show me the work. The web2.0calc.com is great for solving the problem, but I'd like to understand the process--in other ways see all the steps.
 Mar 22, 2014
 #2
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geofjen@gmail.com:

in the following expression: x-(21*x\100)=275000 how does that become x=27500000\79?



Hello, lets start:
x-(21x/100) = 275000 => Now we just subtract x from the fraction 21x/100. Here's how: http://www.mathsisfun.com/fractions_subtraction.html
And we got =>
[list]
  • (100x-21x)/100 = 275000 => 79x/100 = 275000 =>[/*:m][/list:u]
    Now we multiply with 100 from both sides:
    [list]
  • => 100 * (79x/100) = 100 * 275000 => 79x=27500000[/*:m][/list:u]
    Then, we divide with 79 from both sides:
    [list]
  • => 79x/79 = 27500000/79 => x = 27500000/79[/*:m][/list:u]

    If you need more help, you can reply here

    Dms
  •  Mar 22, 2014
     #3
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    0
    Thanks Dms,

    please note Geof that the fraction line has to be a forward slash (you used a back slash)

    If you need more help or clarification don't hesitate to ask.
     Mar 23, 2014

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