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# Old guy brushing up on basic Algebra

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in the following expression: x-(21*x\100)=275000 how does that become x=27500000\79?
Mar 22, 2014

### 3+0 Answers

#1
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What I want someone to do is show me the work. The web2.0calc.com is great for solving the problem, but I'd like to understand the process--in other ways see all the steps.
Mar 22, 2014
#2
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geofjen@gmail.com:

in the following expression: x-(21*x\100)=275000 how does that become x=27500000\79?

Hello, lets start:
x-(21x/100) = 275000 => Now we just subtract x from the fraction 21x/100. Here's how: http://www.mathsisfun.com/fractions_subtraction.html
And we got =>
[list]
• (100x-21x)/100 = 275000 => 79x/100 = 275000 =>[/*:m][/list:u]
Now we multiply with 100 from both sides:
[list]
• => 100 * (79x/100) = 100 * 275000 => 79x=27500000[/*:m][/list:u]
Then, we divide with 79 from both sides:
[list]
• => 79x/79 = 27500000/79 => x = 27500000/79[/*:m][/list:u]

If you need more help, you can reply here

Dms
•  Mar 22, 2014
#3
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Thanks Dms,

please note Geof that the fraction line has to be a forward slash (you used a back slash)

If you need more help or clarification don't hesitate to ask.
Mar 23, 2014