+185 A quadratic of the form \(-2x^2 + bx + c\) has roots of \(x = 3 + \sqrt{5}\) and \(x = 3 - \sqrt{5}.\) The graph of \(y = -2x^2 + bx + c\) is a parabola. Find the vertex of this parabola.
I am really confused and I don't know what to do. Could anyone please explain with their answer? Thank you!
