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One fair die has faces 1, 1, 2, 2, 3, 3 and another has faces 4, 4, 5, 5, 6, 6. The dice are rolled and the numbers on the top faces are added. What is the probability that the sum will be odd?

 Apr 10, 2015

Best Answer 

 #1
avatar+33661 
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prob 1st die odd and 2nd die even = (2/3)*(2/3) = 4/9

prob 1st die even and 2nd die odd = (1/3)*(1/3) = 1/9

 

So probability that sum is odd = 4/9 + 1/9 = 5/9

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 Apr 10, 2015
 #1
avatar+33661 
+5
Best Answer

prob 1st die odd and 2nd die even = (2/3)*(2/3) = 4/9

prob 1st die even and 2nd die odd = (1/3)*(1/3) = 1/9

 

So probability that sum is odd = 4/9 + 1/9 = 5/9

.

Alan Apr 10, 2015

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