One leg of a right triangle is 2 cm longer than the other leg. How long should the shorter leg be to ensure that the area of the triangle is greater than or equal to 4 cm^2?
+130536 Let the shorter leg = x so...the longer leg = x + 2
And we have that
(1/2)(x)(x + 2) ≥ 4 multiply both sides by 2
x(x+2) ≥ 8 simplify
x^2 +2x - 8 ≥ 0 let's just use a graphical method to solve this.....here's the graph...
https://www.desmos.com/calculator/gooq4e4ucf
We must reject any negative values for x and we must also reject any values in the interval [0, 2) because these values make the inequality < 0...thus...the values that solve the inequality are found in the interval [2, ∞ )
+130536 Let the shorter leg = x so...the longer leg = x + 2
And we have that
(1/2)(x)(x + 2) ≥ 4 multiply both sides by 2
x(x+2) ≥ 8 simplify
x^2 +2x - 8 ≥ 0 let's just use a graphical method to solve this.....here's the graph...
https://www.desmos.com/calculator/gooq4e4ucf
We must reject any negative values for x and we must also reject any values in the interval [0, 2) because these values make the inequality < 0...thus...the values that solve the inequality are found in the interval [2, ∞ )
