One number is 3 less than a second number. Twice the second number is 4 less than 3 times the first. Find the smaller of the two numbers

first number=x

second number=y

y-3=x

2y=3x-4

Solve.

2y-6=2x

-6=-x+4

-2=x

x=2

NOW FIND Y, IF Y IS SMALLER

Let the first number = x

And the second number = x + 3

And we know that

2(x + 3) + 4 = 3x simplify

2x + 6 + 4 = 3x

2x + 10 = 3x

10 = x = the smaller number