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One number is 3 less than a second number. Twice the second number is 4 less than 3 times the first. Find the smaller of the two numbers

 Feb 25, 2019
 #1
avatar+85 
+2

first number=x

second number=y

 

y-3=x

2y=3x-4

 

Solve. 

 

2y-6=2x

2y=3x-4

 

-6=-x+4

 

-2=x

 

x=2

 

NOW FIND Y, IF Y IS SMALLER

 Feb 25, 2019
 #2
avatar+101762 
0

Let the first number = x

And the second number  = x + 3

And we know that

 

2(x + 3) + 4  = 3x     simplify

 

2x + 6 + 4  =  3x

 

2x + 10 =  3x

 

10 =  x   =  the smaller number

 

 

cool cool cool

 Feb 25, 2019

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