One number is 6 more than another. The difference between their squares is 132. What are the numbers?
Let
x=first number
x+6=second number
(x + 6)^2 - x^2 = 132
x2 + 12x + 36 - x^2- 132 = 0
12x + 36 = 132
12x = 96
x = 8 and x + 6 = 14
Therefore, the numbers will be 8 and 14.
Hope this helped!
Let
x=first number
x+6=second number
(x + 6)^2 - x^2 = 132
x2 + 12x + 36 - x^2- 132 = 0
12x + 36 = 132
12x = 96
x = 8 and x + 6 = 14
Therefore, the numbers will be 8 and 14.
Hope this helped!