I'm giving a problem to solve for x and I know how to do most 1 varible equations but I'm a little fuzzy on what to do for this type
\(\frac{(x + 20)}{2} = 3x\)
Thanks so much for your help and time you spend teaching me how to understand the conept.
\(\frac{(x+20)}{2}=3x\)
To take out that fraction multiply both sides by 2
\(\frac{(x+20)}{2}*2=3x*2\)
\(x+20=6x\)
Then to cancle out the 20 subtract 20 on both sides
\(x + 20 - 20 = 6x - 20\)
\(x=6x-20\)
To combine terms subtract 6x on both sides
\(x-6x=6x-20-6x\)
\(-5x=-20\)
Then to single out the x on the left divide both sides by -5
\(\frac{-5x}{-5}=\frac{-20}{-5}\)
Simplify
\(x = 4\)
Your answer for x would be 4
Hope this helps ;P
Try me XD I went through years of pinching I've learned to bear the pain XD one day I'll dare you to give your best shot. (Trust me you won't suceed you won't get a whimper or a wince XD)
BTW I like how you edit the response to say "I'm dead" XD, but you said you were okay with me calling you that you said I was premitted to use the term XD