Le x*y = (x - y)/(x^2 + y^2). What is the value of 1/2*(2/3*3/4)*(2/3*3/4))?
+128474 (1/2) ((2/3 * 3/4) * (2/3 * 3/4) )
(2/3 * 3/4) = ( 2/3 - 3/4) / ( (2/3)^2 + (3/4)^2 ) = (-1/12) / ( 4/9 - 9/16) = ( -1/12) / ( -17/144) =
12/17
So
(1/2) * ( 12/17 * 12/17) = (1/2) * ( [ 12/17 - 12/17 ] / [ (12/17)^2 + (12/17)^2 ]) = (1/2) * 0 =
(1/2 - 0 ) / [ (1/2)^2 + 0^2 ] = (1/2) / (1/4) = ( 4/1) * (1/2) = 4/2 = 2
