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Le x*y = (x - y)/(x^2 + y^2).  What is the value of 1/2*(2/3*3/4)*(2/3*3/4))?

 Jul 19, 2022
 #1
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(1/2) ((2/3 * 3/4) * (2/3 * 3/4) )

 

(2/3 * 3/4)     =   ( 2/3 - 3/4)   / ( (2/3)^2 + (3/4)^2 )   =   (-1/12) / ( 4/9 - 9/16)  = ( -1/12) / ( -17/144)  =

 

12/17

 

So

 

(1/2) * ( 12/17 * 12/17)   =  (1/2) * ( [ 12/17 - 12/17 ]  / [ (12/17)^2 + (12/17)^2 ])  =  (1/2) * 0 =

 

(1/2 - 0 )  / [ (1/2)^2 + 0^2 ]   =   (1/2)  / (1/4)  = ( 4/1)  * (1/2)  =  4/2    = 2 

 

 

cool cool cool

 Jul 19, 2022

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