p(12)=12! xp(x-1)=(x-12)p(x) x=?

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622

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p(12)=12!, x*p(x-1)=(x-12)*p(x)

x=?

Guest Feb 25, 2015

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Best Answer

+23254

+5

If p(12) = 12! means that p(x) = x!,

then x*p(x-1) = x*(x-1)! = x!

and (x-12)*p(x) = (x-12)*x!

Therefore: x*(p-1) = (x-12)p(x)

---> x! = (x-12)*x!

Divide both sides by x!:

---> 1 = X - 12

---> X = 13

geno3141 Feb 25, 2015

1⁺⁰ Answers

+23254

+5

Best Answer

If p(12) = 12! means that p(x) = x!,

then x*p(x-1) = x*(x-1)! = x!

and (x-12)*p(x) = (x-12)*x!

Therefore: x*(p-1) = (x-12)p(x)

---> x! = (x-12)*x!

Divide both sides by x!:

---> 1 = X - 12

---> X = 13

geno3141 Feb 25, 2015

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