91 is the answer
What is the procedure to solve a problem like this?
A number is palindromic, if it is the same backwards as forwards.
Of the largest palindrome made from the product of two two-digit numbers, find one of the numbers.
a) 92 b) 89 c) 90 d) 91
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The biggest possible number is 99 times 92 = 9108
The first palindromic number less than 9108 is 9009
I tried 9009 divided by 89 and 9009 divided by 91
since 9009 is odd I knew the 2 even ones would not go into it
9009 divided by 91 = 99 exactly so
91 is the answer.