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A parabola has zeros at -6 and 10. Its vertex is located at (2, 16). Determine the equation of the quadratic in factored form.

 Mar 1, 2021
 #1
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Using  the vertex form  :

 

y  = a ( x - 2)^2  +  16

 

The point  ( 10, 0 )  is on the graph

 

0  = a  ( 10 - 2)^2  + 16

 

-16  =  a ( 8)^2  

 

-16 = a * 64

 

-16 / 64   = a    =  -1/4

 

y = (-1/4) ( x - 10) ( x + 6)

 

 

cool cool cool

 Mar 1, 2021

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