A parabola has zeros at -6 and 10. Its vertex is located at (2, 16). Determine the equation of the quadratic in factored form.
Using the vertex form :
y = a ( x - 2)^2 + 16
The point ( 10, 0 ) is on the graph
0 = a ( 10 - 2)^2 + 16
-16 = a ( 8)^2
-16 = a * 64
-16 / 64 = a = -1/4
y = (-1/4) ( x - 10) ( x + 6)
