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The line \(y - x \sqrt{3} + 3 = 0\) intersects the parabola \(2y^2 = 2x + 3 \) at points \(A\) and \(B \) Let \(P = (\sqrt{3},0).\) Find \(|AP - BP|. \)

 Nov 11, 2019
 #1
avatar+11731 
+1

The line  intersects the parabola  at points A and B.

laugh

 Nov 11, 2019

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