How do I find the axis of symmetry of 6x2+11x-35?
6x^2+11x-35
In the form ax^2 + bx - c.......the axis of symmetry is given by :
x = -b/2a where b = 11 and a = 2 ..... so we have...
x = -11/ (2*6) = -11/12
So, this vertical line represents the axis of symmetry.
