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need help

 

 Jul 7, 2020
 #1
avatar+28021 
+1

Hint:   Look at the vertex   2, 0

    when x = 2    the equation for y  = 0         do any of these equations work?

 Jul 7, 2020
 #2
avatar+10583 
+1

Write in vertex form.

\(y=-x^2-4\)

 

Hello guest!

 

\(\\ y=-1x^2-4\)

 

\(f (x) = a(x - h)2 + k\)

(h, k) is the vertex of the parabola.

 

\(a=-1\)

\(y=-x^2-4\\ \frac{dy}{dx}=-2x=0\\ x_{max}=0\)

\(h=0\)

 

\(y_{max}=k=-x_{max}^2-4\\ y_{max}=k=0-4\)

\(k=-4 \)

 

\(f (x) = a(x - h)^2 + k\\ f (x) = -1(x - 0)^2 -4\)

 

The equation of the parabola in vertex fotm is \(f (x) = -1(x - 0)^2 -4.\)

You can solve the other tasks yourself based on the model.

laugh  !

 Jul 7, 2020
edited by asinus  Jul 7, 2020

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