parabola question

Hint:   Look at the vertex   2, 0

    when x = 2    the equation for y  = 0         do any of these equations work?

Write in vertex form.

\(y=-x^2-4\)

Hello guest!

\(\\ y=-1x^2-4\)

\(f (x) = a(x - h)2 + k\)

(h, k) is the vertex of the parabola.

\(a=-1\)

\(y=-x^2-4\\ \frac{dy}{dx}=-2x=0\\ x_{max}=0\)

\(h=0\)

\(y_{max}=k=-x_{max}^2-4\\ y_{max}=k=0-4\)

\(k=-4 \)

\(f (x) = a(x - h)^2 + k\\ f (x) = -1(x - 0)^2 -4\)

The equation of the parabola in vertex fotm is \(f (x) = -1(x - 0)^2 -4.\)

You can solve the other tasks yourself based on the model.

  !