The parabola y=ax^2+bx+c is graphed below. Find a+b+c. (The grid lines are one unit apart.)
Find a+b+c.
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The functional equation of the parabola shown is:
f(x)=(x−1)2−4=x2−2x−3
a=1b=−2c=−3a+b+c=−4
!
Let f(x)=ax2+bx+c. Note that f(1)=a⋅12+b⋅1+c=a+b+c, so a+b+c=f(1)=−4.