The vertex of a parabola is at (12,-4) and its axis of symmetry is vertical. One of the x-intercepts is at \((18,0)\). What is the x-coordinate of the other x-intercept?
+2668 12 + 6 = 18
12 - 6 = 6
The x-coordinate of the other x-intercept is \(\color{red} 6\) by symmetry
