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The graph of y=ax^2+bx+c is given below, where a, b, and c are integers. Find a-b+c.

 

 Apr 25, 2022
 #1
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1 and - 2  are roots     and  the point   (0, -2)  is on the graph

 

So

 

a ( 0 - 1) (0 + 2)  =   -2

 

a ( -1) ( 2)  = -2

 

-2a =  -2

 

a  = 1

 

So

 

The  parabola is

 

y = a ( x - 1) ( x + 2)

 

y = a ( x^2 + x - 2)

 

 y = 1x^2  + 1x  - 2

 

a +  b +  c  =     1 + 1    - 2     =     0

 

 

cool cool cool

 Apr 25, 2022

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