The red parabola shown is the graph of the equation ay^2 + by + c = x. Find a + b + c.
Plug in the point \((0,0)\) into the equation.
This gives us: \(0a + 0b + c = 0 \), meaning \(c = 0 \).
Now, plug in the point \((1,2)\) into the equation. This gives us: \(1 =4a + 2b\)
Lastly, plug in the point \((1,-2)\) into the equation. This gives us \(1 = 4a - 2b\)
Solving this system, we find \(b = 0 \) and \(a = {1 \over 4 }\).
Thus, \(a + b + c = \color{brown}\boxed{1 \over 4}\)
Plug in the point \((0,0)\) into the equation.
This gives us: \(0a + 0b + c = 0 \), meaning \(c = 0 \).
Now, plug in the point \((1,2)\) into the equation. This gives us: \(1 =4a + 2b\)
Lastly, plug in the point \((1,-2)\) into the equation. This gives us \(1 = 4a - 2b\)
Solving this system, we find \(b = 0 \) and \(a = {1 \over 4 }\).
Thus, \(a + b + c = \color{brown}\boxed{1 \over 4}\)