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# parabola

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Find the vertex of the parabola x = -2y^2 + 12y - 15.

Jun 30, 2020

We complete the square to get $$y=-2(y-3)^2+3$$. The vertex is (h, k). Therfore the vertex of the parabola $$x = -2y^2 + 12y - 15\ \text {is} \ \boxed{(3, 3)}.$$