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What is the vertex of the graph of f(x) = 8x^2 - 64x?

 Sep 8, 2020
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The 'x' coordinate will be   - b/2a   =  - -64/16 = 4

the 'y' coordinate will be       8 ( 4)^2  - 64(4) = -128     ( found by substituting '4' into the equation for 'x')

 Sep 8, 2020

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