What is the vertex of the graph of f(x) = 8x^2 - 64x?
The 'x' coordinate will be - b/2a = - -64/16 = 4
the 'y' coordinate will be 8 ( 4)^2 - 64(4) = -128 ( found by substituting '4' into the equation for 'x')
+36916 
