Suppose that we have an equation y = ax^2 + bx + c whose graph is a parabola with vertex (3,4), vertical axis of symmetry, and contains the point (1,0). What is (a,b,c)?
Vertex form of parabola
y = a (x-3)^2 +4 sub in point to find a = -1
y = -(x-3)^2 + 4
= -x^2 +6x-9 + 4
y = -x^2 + 6x - 5 you can finish from here......
