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A parabola ax^2+bx+c contains the points (-1,0), (0,5), and (-5,0). Find the value 100a+10b+c.

 Jul 19, 2022
 #1
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x = -1     and  x =  -5 are roots so

 

y =  a ( x +1) ( x + 5)          and (0,5)  is a  point on the graph......so.....

 

5 =  a ( 0+ 1) ( 0 + 5)

 

5  =  a (5)

 

a = 1

 

So we have

 

y = ( x + 1) ( x + 5)

 

y = x^2  + 6x  +  5

 

100(1)  + 10(6)  +  5  =    165

 

 

cool cool cool

 Jul 19, 2022

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