+0  
 
0
39
1
avatar

Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (1,-1). Express your answer in the form "ax^2+bx+c".

 Feb 2, 2021
 #1
avatar
0

Vertex form will be 

   a (x-2)^2 + 4  = y      contains the point 1,-1     substitute this in

 

   a (1-2)^2 + 4 = -1

        a + 4 = -1        so a = -5

 

-5 ( x-2)^2 +4 = y

-5x^2 +20x-16 = y

 Feb 2, 2021

69 Online Users

avatar
avatar
avatar
avatar