+0  
 
0
28
1
avatar

Find the vertex and focus d the parabola: x^2+6x+16y+121=0

 Feb 15, 2021
 #1
avatar+29086 
+1

x^2+6x+16y+121=0    re-arrange to 'vertex form'    (this is one way to do it)

16y = -x^2-6x - 121

 

16 y =  -1 (x^2 + 6x) -121

y = -1/16 (x+3)^2  -  (9-121) /16

                    = -1/16 (x+3)2 -         vertex =   -3,-7      (this is (h,k)    a = -1/16)

 

 

focus =  h, k+ 1/4a     =    -3 , -11

 Feb 15, 2021
edited by ElectricPavlov  Feb 15, 2021

90 Online Users

avatar
avatar
avatar
avatar
avatar
avatar
avatar