Find the vertex and focus d the parabola: x^2+6x+16y+121=0
x^2+6x+16y+121=0 re-arrange to 'vertex form' (this is one way to do it)
16y = -x^2-6x - 121
16 y = -1 (x^2 + 6x) -121
y = -1/16 (x+3)^2 - (9-121) /16
= -1/16 (x+3)2 - 7 vertex = -3,-7 (this is (h,k) a = -1/16)
focus = h, k+ 1/4a = -3 , -11
+37157 
