The vertex of the parabola described by the equation 3y=2x^2-16x+18-x^2+12x is (m, n). What is m+n?
3y = 2x^2 -16x + 18 - x^2 + 12x simplify as
3y = x^2 - 4x + 18 divide through by 3
y = (1/3)x^2 - (4/3)x + 6
m = (4/3) / ( 2 *1/3) = (4/3) / (2/3) = 2
n = (1/3)^2^2 - (4/3)(2) + 6 = (4/3) - 8/3 + 6 = 14/3
m + n = 2 + 14/3 = 20 / 3
