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Find the vertex of the graph of the equation $x - y^2 + 8y = 13 + 2y + y^2 - 7y - 14$.

 Jan 12, 2024

Best Answer 

 #1
avatar+36923 
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=     x = 2y^2 - 13y -1     arrange into vertex form 

         x = 2 ( y^2 - 6.5 y)  - 1

            = 2 ( y- 3.25)^2  - 29 1/8        shows vertex = (  - 22 1/8  ,  3.75  ) 

 Jan 12, 2024
 #1
avatar+36923 
+1
Best Answer

=     x = 2y^2 - 13y -1     arrange into vertex form 

         x = 2 ( y^2 - 6.5 y)  - 1

            = 2 ( y- 3.25)^2  - 29 1/8        shows vertex = (  - 22 1/8  ,  3.75  ) 

ElectricPavlov Jan 12, 2024

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