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Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (-1,-1). Express your answer in the form "ax^2 + bx + c".

 May 14, 2021
 #1
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vertecx form of parabola with vertex ( 2,4)

y   =  a ( x-2)^2 + 4     sub int e point given (-1,-1) to calculate the vlaue of 'a'

-1 = a ( -1-2)2 + 4

-1 = 9a + 4

-5 = 9a

a = - 5/9

 

so the equation becomes    y =- 5/9 (x-2)^2 + 4     expand to get into the reqested form

                                            y = - 5/9 x^2 +20/9 x + 16/9   

 May 14, 2021

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