Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (-1,-1). Express your answer in the form "ax^2 + bx + c".
+36916 vertecx form of parabola with vertex ( 2,4)
y = a ( x-2)^2 + 4 sub int e point given (-1,-1) to calculate the vlaue of 'a'
-1 = a ( -1-2)2 + 4
-1 = 9a + 4
-5 = 9a
a = - 5/9
so the equation becomes y =- 5/9 (x-2)^2 + 4 expand to get into the reqested form
y = - 5/9 x^2 +20/9 x + 16/9
