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The graph of a certain quadratic y = ax^2 + bx + c is a parabola with vertex  (-4,0)  which passes through the point (1,75) What is the value of a?

 May 15, 2021
 #1
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Vertex (-4,0)

Vertex form     y = a ( x+4)^2 + 0

                      sub in the point (1,75) to calculate 'a'

                           75 = a ( 1 +4)^2      so a = 3

 May 15, 2021

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