The graph of $y = ax^2 + bx + c$ has an axis of symmetry of $x = -1.$ If $a = 2,$ then find $b.$
View other drafts
The axis of symmetry of the graph of y=ax2+bx+c is x=−2ab. In general, the axis of symmetry is a vertical line, so we have −2ab=−1. Solving for b, we find b=2a=16.