The vertex of the parabola described by the equation 3y=2x^2+16x+28 is (m, n). What is m+n?
+526 \(3y=2x^2+16x+28\)
\(=2(x^2+8x+16)-2\)
\(y={2\over 3}(x+4)^2-{2\over 3}\)
This equation is similar to \(y=a(x-h)^2+k\) in which (h,k) is the vertex
⇒ (m,n) = (-4, -2/3)
\(m+n=-4-{2\over 3} = -{14\over 3}\)
