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The vertex of the parabola described by the equation 3y=2x^2+16x+28 is (m, n). What is m+n?

 Jun 22, 2021
 #1
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\(3y=2x^2+16x+28\)

      \(=2(x^2+8x+16)-2\)

\(y={2\over 3}(x+4)^2-{2\over 3}\)

 

This equation is similar to  \(y=a(x-h)^2+k\)  in which (h,k) is the vertex 

⇒ (m,n) = (-4, -2/3)

 

 \(m+n=-4-{2\over 3} = -{14\over 3}\) 

 Jun 23, 2021

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