The vertex of a parabola is at (12,-4), and its axis of symmetry is vertical. One of the x-intercepts is at (18,0). What is the x-coordinate of the other x-intercept?
Because of symmetry about the vertex ....the other x intercept =
(12 - (18 - 12) , 0 ) = ( 12 - 6 , 0 ) = (6 , 0)
