Find the vertex of the graph of the equation $x - y^2 + 8y = 13 + 2y + y^2 - 7y - 14$.
Simplify as
x = 2y^2 -13y - 1
y coordinate of the vertex = 13(2*2) = 13/4
x coordinate of the vertex = 2(13/4)^2 - 13 (13/4) - 1 = -177/8
Vertex = ( -177/8 , 13/4) = (-22.125 , 3.25)
+1167 
