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Find the vertex of the graph of the equation $x - y^2 + 8y = 13 + 2y + y^2 - 7y - 14$.

 Mar 15, 2024
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Simplify as

 

x =  2y^2  -13y  - 1

 

y coordinate of the  vertex  = 13(2*2)  = 13/4

 

x coordinate of the vertex = 2(13/4)^2  - 13 (13/4)  - 1   =  -177/8

 

Vertex =  ( -177/8 , 13/4)  = (-22.125 , 3.25)

 

 

cool cool cool

 Mar 15, 2024

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