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Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (1,-11). Express your answer in the form "ax^2+bx+c".

 Jul 6, 2021
 #1
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Vertex form of parabola

 

y = a ( x- 2)^2 + 4        sub in point to calulate  a

-11 = a(-1)^2 + 4

 a = -15

 

 

y = -15 (x-2)^2 + 4

  = -15x^2 + 60x-56

 Jul 6, 2021

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