What is the perimeter of parallelogram WXYZ?
Note that WX = YZ and WZ = XY.
WX = 4 by the distance formula (or you can just count squares).
WZ = \(\sqrt{(-3-[-2])^2+(-1-4)^2}=\sqrt{1+25}=\sqrt{26}\)by the distance formula.
WX+XY+YZ+WZ= 4 x 2 + 2\(\sqrt{26}\) = 8 + 2\(\sqrt{26}\)
+308 
