parallelogram

Given parallelogram ABCD, find x, y, and z.

Hello Guest!

$z-15°+ 2z=180°\\ 3z=165°$

$z=55°$

$x=90°+(90°-(z-15°))\\ x=90°+(90°-(55°-15°))$

$x=140°$

$y=90°-(2z-90°)\\ y=90°-(2\cdot 55°-90°)$

$y=70°$

  !