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Given parallelogram ABCD, find x, y, and z.

 

 Feb 10, 2021
 #1
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Given parallelogram ABCD, find x, y, and z.

 

Hello Guest!

 

\(z-15°+ 2z=180°\\ 3z=165°\)

\(z=55°\)

\(x=90°+(90°-(z-15°))\\ x=90°+(90°-(55°-15°))\)

\(x=140°\)

\(y=90°-(2z-90°)\\ y=90°-(2\cdot 55°-90°) \)

\(y=70°\)

laugh  !

 Feb 10, 2021
edited by asinus  Feb 10, 2021
edited by asinus  Feb 10, 2021
 #2
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last step should be y = 40  

Guest Feb 10, 2021
 #3
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(z - 15) + 2z = 180

 

3z = 195

 

z = 65

 

x = 2z = 130

 

y = z - 15 = 50

Guest Feb 10, 2021

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