We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
96
10
avatar+1346 

 

This is connected to a part 1 . Melody and Ginger were helping me but if anyone could help as well

 

not sure what i would do here

 Sep 24, 2019
edited by jjennylove  Sep 24, 2019
 #1
avatar+19774 
+2

AC     4.6x1016

______________

Merc  5.79x1010

 

=.79447323x106

=794,4732.3 times farther

 Sep 25, 2019
 #6
avatar+1346 
0

As it goes for question 4, since I am using AU units would I solve it differently ? and do 5.5786392/-0.413412695 ? and whatever that equals is the answer? or would I have to use the metre distance for that ?

jjennylove  Sep 26, 2019
 #2
avatar+105503 
+2

Here you go.

I based the log on  AU (astronomical units)  but you could do it straight from the metre distance if you prefer.

It is just a matter of scale you have to say what your logarithmic scale is based on.

 

 Sep 25, 2019
 #3
avatar+1346 
0

Wow ,thank you for physcially creating one for me. I really apprectiate it! Would this be able to tranfer to the same number line as part 1?

 

If so, also would the vaues change if Increased my scales ? because I am going need to include all the stars and planets but in the number line you provided for the first part it only included the first 8 ,  i was tihnking of doing for evey 1 cm = 2000 km?

jjennylove  Sep 25, 2019
 #4
avatar+105503 
+2

The logarithmic graph I have done includes the stars as well as the plantets.

Yes you can change it to a number line.

Just push all the entitiies left so that they line up on the vertical axis.

Melody  Sep 25, 2019
 #5
avatar+1346 
+1

Just finsihed up creating my own graph and as well jsut used the AU units, I felt it to be a bit easier that way. smiley This is all making sense, thank you again for your help ! Theres still some more parts but I am going to go ahead and try doing it myself before I ask any questions.

 

As it goes for question 4, since I am using AU units would I solve it differently ? and do 5.5786392/-0.413412695 ? and wahteer that equals is the answer? or would I have to use the metre distance for that ?

jjennylove  Sep 26, 2019
edited by jjennylove  Sep 26, 2019
 #7
avatar+105503 
+2

The ratio works out the same no matter what units you use.  So long as you use the same units for both measurments.

Melody  Sep 27, 2019
 #8
avatar+1346 
0

i think im going to do it straight from the metre distance , if I were to do that

Lets say I started with Mercury I would plug it like this into the calculator  log 57900000000  which would be 10.76 ?

 

         Mercury    

jjennylove  Sep 29, 2019
 #9
avatar+1346 
0

did i do it correctly?

jjennylove  Sep 30, 2019
 #10
avatar+105503 
0

Yes, looks ok

Melody  Sep 30, 2019

24 Online Users

avatar