This is connected to a part 1 . Melody and Ginger were helping me but if anyone could help as well
not sure what i would do here
AC 4.6x1016
______________
Merc 5.79x1010
=.79447323x106
=794,4732.3 times farther
As it goes for question 4, since I am using AU units would I solve it differently ? and do 5.5786392/-0.413412695 ? and whatever that equals is the answer? or would I have to use the metre distance for that ?
Here you go.
I based the log on AU (astronomical units) but you could do it straight from the metre distance if you prefer.
It is just a matter of scale you have to say what your logarithmic scale is based on.
Wow ,thank you for physcially creating one for me. I really apprectiate it! Would this be able to tranfer to the same number line as part 1?
If so, also would the vaues change if Increased my scales ? because I am going need to include all the stars and planets but in the number line you provided for the first part it only included the first 8 , i was tihnking of doing for evey 1 cm = 2000 km?
The logarithmic graph I have done includes the stars as well as the plantets.
Yes you can change it to a number line.
Just push all the entitiies left so that they line up on the vertical axis.
Just finsihed up creating my own graph and as well jsut used the AU units, I felt it to be a bit easier that way. This is all making sense, thank you again for your help ! Theres still some more parts but I am going to go ahead and try doing it myself before I ask any questions.
As it goes for question 4, since I am using AU units would I solve it differently ? and do 5.5786392/-0.413412695 ? and wahteer that equals is the answer? or would I have to use the metre distance for that ?
The ratio works out the same no matter what units you use. So long as you use the same units for both measurments.
i think im going to do it straight from the metre distance , if I were to do that
Lets say I started with Mercury I would plug it like this into the calculator log 57900000000 which would be 10.76 ?
Mercury